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8x^2+400x-4800=0
a = 8; b = 400; c = -4800;
Δ = b2-4ac
Δ = 4002-4·8·(-4800)
Δ = 313600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{313600}=560$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(400)-560}{2*8}=\frac{-960}{16} =-60 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(400)+560}{2*8}=\frac{160}{16} =10 $
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